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6m^2-23m+10=0
a = 6; b = -23; c = +10;
Δ = b2-4ac
Δ = -232-4·6·10
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{289}=17$$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-23)-17}{2*6}=\frac{6}{12} =1/2 $$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-23)+17}{2*6}=\frac{40}{12} =3+1/3 $
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